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📌 Section 1 is Logical reasoning specially designed for CAT
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SET 1 — 🔍 CAT Level
On January 1st, Rahul invested ₹4000 to purchase the shares of exactly four companies, A, B, C and D, such that he purchased shares worth ₹1000 of each company. From January 2nd to January 8th, at the beginning of each day, he sold all the shares of the company whose share price was the highest, and then purchased, with the money that he had, as many shares as possible of the company whose share price was the lowest. If, on any day, he did not have any shares of the company whose share price was the highest (among the four companies), he did not sell any shares on that day. While purchasing any shares, Rahul used the maximum possible amount of money available with him and carried forward any amount left unused to the next day.
During the given period, he did not invest any additional amount for purchasing shares and he spent all the money that he obtained from selling any share only for purchasing shares. He sells or purchases any shares only at the beginning of the day.
The following graph provides the price of a share of each of the four companies at the beginning of each of the eight days.
Question 1
How many shares of B did Rahul have at the end of the eighth day?
Question 2
What is the maximum number of shares that Rahul sold on any day?
Question 3
The difference in the total number of shares that Rahul had on any two consecutive days was at most:
A. 141
B. 125
C. 150
D. None of the above
Question 4
At the end of Day 8, if Rahul sold all the shares of A, B, C and D that he had, each at ₹40, ₹20, ₹80 and ₹30 respectively, what would be the total amount with Rahul after selling the shares?
A. ₹34000
B. ₹30760
C. ₹31890
D. ₹32540
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✅ Answers & Explanations
Initial shares: A = 20, B = 25, C = 10, D = 50
Day | Highest price company | Sold | Lowest price company | Purchased | Cash left | Final shares |
|---|---|---|---|---|---|---|
Jan 2 | C | 10 C for ₹1100 | A | 36 A | ₹20 | A56, B25, D50 |
Jan 3 | B | 25 B for ₹2250 | D | 75 D | ₹20 | A56, D125 |
Jan 4 | B | No B shares | A | 0 | ₹20 | A56, D125 |
Jan 5 | C | No C shares | D | 0 | ₹20 | A56, D125 |
Jan 6 | A | 56 A for ₹3920 | C | 197 C | ₹0 | C197, D125 |
Jan 7 | D | 125 D for ₹7500 | B | 250 B | ₹0 | B250, C197 |
Jan 8 | B | 250 B for ₹15000 | A | 375 A | ₹0 | A375, C197 |
Total shares at the end of each day
Day | Total shares |
|---|---|
Jan 1 | 105 |
Jan 2 | 131 |
Jan 3 | 181 |
Jan 4 | 181 |
Jan 5 | 181 |
Jan 6 | 322 |
Jan 7 | 447 |
Jan 8 | 572 |
Set 1
1.Shares of B at the end of Day 8 = 0
2.Maximum shares sold on any day = 250
3.Total shares at the end of each day:
Maximum difference between consecutive days = 322 - 181 = 141
Answer: A. 141
4.Final value at given prices:
A = 375 × 40 = ₹15000
C = 197 × 80 = ₹15760
Total = ₹30760
Answer: B. ₹30760
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Stay consistent with your daily practice, challenge your assumptions, and keep sharpening your reasoning skills.
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